Base | Representation |
---|---|
bin | 100101001101011101100… |
… | …1011110100110000010101 |
3 | 200002220112000100020101110 |
4 | 1022122323023310300111 |
5 | 1132242240242140201 |
6 | 14513224143445233 |
7 | 1035325304453214 |
oct | 112327313646025 |
9 | 20086460306343 |
10 | 5114151521301 |
11 | 16a1999232009 |
12 | 6a71a6bb6819 |
13 | 2b13546c5044 |
14 | 13975208307b |
15 | 8d06e01e6d6 |
hex | 4a6bb2f4c15 |
5114151521301 has 8 divisors (see below), whose sum is σ = 6819082761280. Its totient is φ = 3409327314432.
The previous prime is 5114151521299. The next prime is 5114151521341. The reversal of 5114151521301 is 1031251514115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5114151521301 - 21 = 5114151521299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5114151521341) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26646721 + ... + 26837958.
It is an arithmetic number, because the mean of its divisors is an integer number (852385345160).
Almost surely, 25114151521301 is an apocalyptic number.
It is an amenable number.
5114151521301 is a deficient number, since it is larger than the sum of its proper divisors (1704931239979).
5114151521301 is a wasteful number, since it uses less digits than its factorization.
5114151521301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53516555.
The product of its (nonzero) digits is 3000, while the sum is 30.
The spelling of 5114151521301 in words is "five trillion, one hundred fourteen billion, one hundred fifty-one million, five hundred twenty-one thousand, three hundred one".
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