Base | Representation |
---|---|
bin | 1001100001101011… |
… | …00001010010011001 |
3 | 111012102110112200101 |
4 | 10300311201102121 |
5 | 40433230204031 |
6 | 2203253135401 |
7 | 240510602146 |
oct | 46065412231 |
9 | 14172415611 |
10 | 5114303641 |
11 | 2194989027 |
12 | ba892a561 |
13 | 63673ca95 |
14 | 3673373cd |
15 | 1eded4361 |
hex | 130d61499 |
5114303641 has 2 divisors, whose sum is σ = 5114303642. Its totient is φ = 5114303640.
The previous prime is 5114303603. The next prime is 5114303687. The reversal of 5114303641 is 1463034115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3806396416 + 1307907225 = 61696^2 + 36165^2 .
It is a cyclic number.
It is not a de Polignac number, because 5114303641 - 211 = 5114301593 is a prime.
It is a super-2 number, since 2×51143036412 = 52312203464691713762, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5114306641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557151820 + 2557151821.
It is an arithmetic number, because the mean of its divisors is an integer number (2557151821).
Almost surely, 25114303641 is an apocalyptic number.
It is an amenable number.
5114303641 is a deficient number, since it is larger than the sum of its proper divisors (1).
5114303641 is an equidigital number, since it uses as much as digits as its factorization.
5114303641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
The square root of 5114303641 is about 71514.3596839124. The cubic root of 5114303641 is about 1722.9083255898.
Adding to 5114303641 its reverse (1463034115), we get a palindrome (6577337756).
The spelling of 5114303641 in words is "five billion, one hundred fourteen million, three hundred three thousand, six hundred forty-one".
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