Base | Representation |
---|---|
bin | 101111101000010111… |
… | …011101010000101011 |
3 | 11220000020202211212200 |
4 | 233220113131100223 |
5 | 1314220113303111 |
6 | 35254514111243 |
7 | 3460242131052 |
oct | 575027352053 |
9 | 156006684780 |
10 | 51143103531 |
11 | 1a764a48713 |
12 | 9ab387b523 |
13 | 4a90832a50 |
14 | 269248d399 |
15 | 14e4de2256 |
hex | be85dd42b |
51143103531 has 24 divisors (see below), whose sum is σ = 83014897056. Its totient is φ = 30104300160.
The previous prime is 51143103511. The next prime is 51143103541. The reversal of 51143103531 is 13530134115.
It is a happy number.
51143103531 is a `hidden beast` number, since 5 + 114 + 3 + 10 + 3 + 531 = 666.
It is not a de Polignac number, because 51143103531 - 215 = 51143070763 is a prime.
It is a super-2 number, since 2×511431035312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51143103495 and 51143103504.
It is not an unprimeable number, because it can be changed into a prime (51143103511) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9499930 + ... + 9505311.
It is an arithmetic number, because the mean of its divisors is an integer number (3458954044).
Almost surely, 251143103531 is an apocalyptic number.
51143103531 is a deficient number, since it is larger than the sum of its proper divisors (31871793525).
51143103531 is a wasteful number, since it uses less digits than its factorization.
51143103531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19005283 (or 19005280 counting only the distinct ones).
The product of its (nonzero) digits is 2700, while the sum is 27.
Adding to 51143103531 its reverse (13530134115), we get a palindrome (64673237646).
The spelling of 51143103531 in words is "fifty-one billion, one hundred forty-three million, one hundred three thousand, five hundred thirty-one".
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