Base | Representation |
---|---|
bin | 1001100001101011… |
… | …01100010111000111 |
3 | 111012102112211220022 |
4 | 10300311230113013 |
5 | 40433233131444 |
6 | 2203254125355 |
7 | 240511151324 |
oct | 46065542707 |
9 | 14172484808 |
10 | 5114348999 |
11 | 2194a0a111 |
12 | ba895085b |
13 | 636757616 |
14 | 367349b4b |
15 | 1edee29ee |
hex | 130d6c5c7 |
5114348999 has 4 divisors (see below), whose sum is σ = 5115437040. Its totient is φ = 5113260960.
The previous prime is 5114348963. The next prime is 5114349017. The reversal of 5114348999 is 9998434115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5114348999 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5114348999.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5114348399) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 536939 + ... + 546380.
It is an arithmetic number, because the mean of its divisors is an integer number (1278859260).
Almost surely, 25114348999 is an apocalyptic number.
5114348999 is a deficient number, since it is larger than the sum of its proper divisors (1088041).
5114348999 is a wasteful number, since it uses less digits than its factorization.
5114348999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1088040.
The product of its digits is 1399680, while the sum is 53.
The square root of 5114348999 is about 71514.6768083307. The cubic root of 5114348999 is about 1722.9134189808.
The spelling of 5114348999 in words is "five billion, one hundred fourteen million, three hundred forty-eight thousand, nine hundred ninety-nine".
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