5114440401303 has 4 divisors (see below), whose sum is σ = 6819253868408. Its totient is φ = 3409626934200.

The previous prime is 5114440401281. The next prime is 5114440401319. The reversal of 5114440401303 is 3031040444115.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-5114440401303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114440401373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852406733548 + ... + 852406733553.

It is an arithmetic number, because the mean of its divisors is an integer number (1704813467102).

Almost surely, 2^{5114440401303} is an apocalyptic number.

5114440401303 is a deficient number, since it is larger than the sum of its proper divisors (1704813467105).

5114440401303 is a wasteful number, since it uses less digits than its factorization.

5114440401303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1704813467104.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 5114440401303 its reverse (3031040444115), we get a palindrome (8145480845418).

The spelling of 5114440401303 in words is "five trillion, one hundred fourteen billion, four hundred forty million, four hundred one thousand, three hundred three".