Base | Representation |
---|---|
bin | 101111101000011110… |
… | …101101010011010001 |
3 | 11220000101100102011100 |
4 | 233220132231103101 |
5 | 1314221110113431 |
6 | 35255022535013 |
7 | 3460264235352 |
oct | 575036552321 |
9 | 156011312140 |
10 | 51145004241 |
11 | 1a766026751 |
12 | 9ab4437469 |
13 | 4a91049c26 |
14 | 2692825d29 |
15 | 14e516a4e6 |
hex | be87ad4d1 |
51145004241 has 24 divisors (see below), whose sum is σ = 75367436040. Its totient is φ = 33415151616.
The previous prime is 51145004233. The next prime is 51145004279. The reversal of 51145004241 is 14240054115.
51145004241 is a `hidden beast` number, since 5 + 114 + 500 + 4 + 2 + 41 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 70812225 + 51074192016 = 8415^2 + 225996^2 .
It is not a de Polignac number, because 51145004241 - 23 = 51145004233 is a prime.
It is a super-2 number, since 2×511450042412 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51145004641) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 192016 + ... + 373041.
It is an arithmetic number, because the mean of its divisors is an integer number (3140309835).
Almost surely, 251145004241 is an apocalyptic number.
It is an amenable number.
51145004241 is a deficient number, since it is larger than the sum of its proper divisors (24222431799).
51145004241 is a wasteful number, since it uses less digits than its factorization.
51145004241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 565265 (or 565262 counting only the distinct ones).
The product of its (nonzero) digits is 3200, while the sum is 27.
Adding to 51145004241 its reverse (14240054115), we get a palindrome (65385058356).
The spelling of 51145004241 in words is "fifty-one billion, one hundred forty-five million, four thousand, two hundred forty-one".
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