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5115133331531 is a prime number
BaseRepresentation
bin100101001101111010110…
…1101001000100001001011
3200010000001102210100211022
41022123311231020201023
51132301243113102111
614513505415223055
71035361525634546
oct112336555104113
920100042710738
105115133331531
1116a2352461623
126a741b977a8b
132b147cc33a42
1413980661785d
158d0ca30b2db
hex4a6f5b4884b

5115133331531 has 2 divisors, whose sum is σ = 5115133331532. Its totient is φ = 5115133331530.

The previous prime is 5115133331501. The next prime is 5115133331537. The reversal of 5115133331531 is 1351333315115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5115133331531 - 226 = 5115066222667 is a prime.

It is a super-2 number, since 2×51151333315312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5115133331491 and 5115133331500.

It is not a weakly prime, because it can be changed into another prime (5115133331537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557566665765 + 2557566665766.

It is an arithmetic number, because the mean of its divisors is an integer number (2557566665766).

Almost surely, 25115133331531 is an apocalyptic number.

5115133331531 is a deficient number, since it is larger than the sum of its proper divisors (1).

5115133331531 is an equidigital number, since it uses as much as digits as its factorization.

5115133331531 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30375, while the sum is 35.

Adding to 5115133331531 its reverse (1351333315115), we get a palindrome (6466466646646).

The spelling of 5115133331531 in words is "five trillion, one hundred fifteen billion, one hundred thirty-three million, three hundred thirty-one thousand, five hundred thirty-one".