5115313001 has 2 divisors, whose sum is σ = 5115313002. Its totient is φ = 5115313000.

The previous prime is 5115312997. The next prime is 5115313033. The reversal of 5115313001 is 1003135115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3329405401 + 1785907600 = 57701^2 + 42260^2 .

It is a cyclic number.

It is not a de Polignac number, because 5115313001 - 2² = 5115312997 is a prime.

It is not a weakly prime, because it can be changed into another prime (5115313081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557656500 + 2557656501.

It is an arithmetic number, because the mean of its divisors is an integer number (2557656501).

Almost surely, 2^5115313001 is an apocalyptic number.

It is an amenable number.

5115313001 is a deficient number, since it is larger than the sum of its proper divisors (1).

5115313001 is an equidigital number, since it uses as much as digits as its factorization.

5115313001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225, while the sum is 20.

The square root of 5115313001 is about 71521.4163799907. The cubic root of 5115313001 is about 1723.0216626458.

Adding to 5115313001 its reverse (1003135115), we get a palindrome (6118448116).

The spelling of 5115313001 in words is "five billion, one hundred fifteen million, three hundred thirteen thousand, one".