Base | Representation |
---|---|
bin | 1001100001110011… |
… | …10000011001010111 |
3 | 111012111112221221121 |
4 | 10300321300121113 |
5 | 40434021222403 |
6 | 2203333024411 |
7 | 240523205512 |
oct | 46071603127 |
9 | 14174487847 |
10 | 5115414103 |
11 | 2195577368 |
12 | ba9185107 |
13 | 636a3b367 |
14 | 367545d79 |
15 | 1ee1533bd |
hex | 130e70657 |
5115414103 has 4 divisors (see below), whose sum is σ = 5130071800. Its totient is φ = 5100756408.
The previous prime is 5115414097. The next prime is 5115414113. The reversal of 5115414103 is 3014145115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5115414103 - 229 = 4578543191 is a prime.
It is a super-2 number, since 2×51154141032 = 52334922890342589218, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5115414113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7328325 + ... + 7329022.
It is an arithmetic number, because the mean of its divisors is an integer number (1282517950).
Almost surely, 25115414103 is an apocalyptic number.
5115414103 is a deficient number, since it is larger than the sum of its proper divisors (14657697).
5115414103 is a wasteful number, since it uses less digits than its factorization.
5115414103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14657696.
The product of its (nonzero) digits is 1200, while the sum is 25.
The square root of 5115414103 is about 71522.1231717851. The cubic root of 5115414103 is about 1723.0330141694.
Adding to 5115414103 its reverse (3014145115), we get a palindrome (8129559218).
The spelling of 5115414103 in words is "five billion, one hundred fifteen million, four hundred fourteen thousand, one hundred three".
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