Search a number
-
+
51156731713 is a prime number
BaseRepresentation
bin101111101001001011…
…011100011101000001
311220001012102020020011
4233221023130131001
51314232110403323
635300122144521
73460466021263
oct575113343501
9156035366204
1051156731713
111a77170677a
129ab8352141
134a935c4b69
1426941d9b33
1514e61d520d
hexbe92dc741

51156731713 has 2 divisors, whose sum is σ = 51156731714. Its totient is φ = 51156731712.

The previous prime is 51156731669. The next prime is 51156731723. The reversal of 51156731713 is 31713765115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26086126144 + 25070605569 = 161512^2 + 158337^2 .

It is a cyclic number.

It is not a de Polignac number, because 51156731713 - 233 = 42566797121 is a prime.

It is a super-2 number, since 2×511567317132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51156731723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25578365856 + 25578365857.

It is an arithmetic number, because the mean of its divisors is an integer number (25578365857).

Almost surely, 251156731713 is an apocalyptic number.

It is an amenable number.

51156731713 is a deficient number, since it is larger than the sum of its proper divisors (1).

51156731713 is an equidigital number, since it uses as much as digits as its factorization.

51156731713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 66150, while the sum is 40.

The spelling of 51156731713 in words is "fifty-one billion, one hundred fifty-six million, seven hundred thirty-one thousand, seven hundred thirteen".