Base | Representation |
---|---|
bin | 10111010000111111001110… |
… | …00011111001100000100011 |
3 | 20201010222002020002000110012 |
4 | 23220133213003321200203 |
5 | 23201211200344142124 |
6 | 300451051233355135 |
7 | 13530164010636653 |
oct | 1350374703714043 |
9 | 221128066060405 |
10 | 51161232021539 |
11 | 153353a1784162 |
12 | 58a3481108aab |
13 | 2271639281a53 |
14 | c8c30702c363 |
15 | 5dac4b0c6e0e |
hex | 2e87e70f9823 |
51161232021539 has 2 divisors, whose sum is σ = 51161232021540. Its totient is φ = 51161232021538.
The previous prime is 51161232021509. The next prime is 51161232021593. The reversal of 51161232021539 is 93512023216115.
Together with next prime (51161232021593) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51161232021539 - 244 = 33569045977123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51161232021496 and 51161232021505.
It is not a weakly prime, because it can be changed into another prime (51161232021509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25580616010769 + 25580616010770.
It is an arithmetic number, because the mean of its divisors is an integer number (25580616010770).
Almost surely, 251161232021539 is an apocalyptic number.
51161232021539 is a deficient number, since it is larger than the sum of its proper divisors (1).
51161232021539 is an equidigital number, since it uses as much as digits as its factorization.
51161232021539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 41.
The spelling of 51161232021539 in words is "fifty-one trillion, one hundred sixty-one billion, two hundred thirty-two million, twenty-one thousand, five hundred thirty-nine".
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