Base | Representation |
---|---|
bin | 101111101010101101… |
… | …101001011011011011 |
3 | 11220002222212010100011 |
4 | 233222231221123123 |
5 | 1314310203144341 |
6 | 35302442022351 |
7 | 3461230600435 |
oct | 575255513333 |
9 | 156088763304 |
10 | 51182474971 |
11 | 1a785199aa1 |
12 | 9b04aa79b7 |
13 | 4a98a39464 |
14 | 26977bb655 |
15 | 14e85bcb81 |
hex | beab696db |
51182474971 has 2 divisors, whose sum is σ = 51182474972. Its totient is φ = 51182474970.
The previous prime is 51182474951. The next prime is 51182475013. The reversal of 51182474971 is 17947428115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51182474971 - 25 = 51182474939 is a prime.
It is a super-3 number, since 3×511824749713 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (51182474951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25591237485 + 25591237486.
It is an arithmetic number, because the mean of its divisors is an integer number (25591237486).
Almost surely, 251182474971 is an apocalyptic number.
51182474971 is a deficient number, since it is larger than the sum of its proper divisors (1).
51182474971 is an equidigital number, since it uses as much as digits as its factorization.
51182474971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 564480, while the sum is 49.
The spelling of 51182474971 in words is "fifty-one billion, one hundred eighty-two million, four hundred seventy-four thousand, nine hundred seventy-one".
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