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51196903 = 311651513
BaseRepresentation
bin1100001101001…
…1001111100111
310120100001221121
43003103033213
5101101300103
65025154411
71161111052
oct303231747
9116301847
1051196903
1126998a9a
121518ba07
13a7b7134
146b29a99
1547646bd
hex30d33e7

51196903 has 4 divisors (see below), whose sum is σ = 52848448. Its totient is φ = 49545360.

The previous prime is 51196883. The next prime is 51196909. The reversal of 51196903 is 30969115.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30969115 = 56193823.

It is a cyclic number.

It is not a de Polignac number, because 51196903 - 217 = 51065831 is a prime.

It is a super-2 number, since 2×511969032 = 5242245753582818, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51196909) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 825726 + ... + 825787.

It is an arithmetic number, because the mean of its divisors is an integer number (13212112).

Almost surely, 251196903 is an apocalyptic number.

51196903 is a deficient number, since it is larger than the sum of its proper divisors (1651545).

51196903 is a wasteful number, since it uses less digits than its factorization.

51196903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1651544.

The product of its (nonzero) digits is 7290, while the sum is 34.

The square root of 51196903 is about 7155.2011152727. The cubic root of 51196903 is about 371.3196195586.

The spelling of 51196903 in words is "fifty-one million, one hundred ninety-six thousand, nine hundred three".

Divisors: 1 31 1651513 51196903