Base | Representation |
---|---|
bin | 10111010010001000000001… |
… | …11111010010010100000111 |
3 | 20201021200222110020201211002 |
4 | 23221010000333102110013 |
5 | 23202331224330210303 |
6 | 300521034133403515 |
7 | 13533046462641023 |
oct | 1351040077222407 |
9 | 221250873221732 |
10 | 51200321725703 |
11 | 1534aa30908497 |
12 | 58aab7019959b |
13 | 2275228874507 |
14 | c9017475d383 |
15 | 5dbc87beb788 |
hex | 2e9100fd2507 |
51200321725703 has 8 divisors (see below), whose sum is σ = 53896533927600. Its totient is φ = 48504255366528.
The previous prime is 51200321725699. The next prime is 51200321725733. The reversal of 51200321725703 is 30752712300215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51200321725703 - 22 = 51200321725699 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51200321725733) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35739698 + ... + 37144671.
It is an arithmetic number, because the mean of its divisors is an integer number (6737066740950).
Almost surely, 251200321725703 is an apocalyptic number.
51200321725703 is a deficient number, since it is larger than the sum of its proper divisors (2696212201897).
51200321725703 is a wasteful number, since it uses less digits than its factorization.
51200321725703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72921361.
The product of its (nonzero) digits is 88200, while the sum is 38.
The spelling of 51200321725703 in words is "fifty-one trillion, two hundred billion, three hundred twenty-one million, seven hundred twenty-five thousand, seven hundred three".
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