Base | Representation |
---|---|
bin | 100101010000001101000… |
… | …1110011011100001100001 |
3 | 200010110201110110010012212 |
4 | 1022200122032123201201 |
5 | 1132341320444212301 |
6 | 14520040411531505 |
7 | 1035624250326101 |
oct | 112403216334141 |
9 | 20113643403185 |
10 | 5120041007201 |
11 | 16a444073aa2a |
12 | 6a836b459b95 |
13 | 2b1a82908743 |
14 | 139b50325201 |
15 | 8d2b60c74bb |
hex | 4a81a39b861 |
5120041007201 has 2 divisors, whose sum is σ = 5120041007202. Its totient is φ = 5120041007200.
The previous prime is 5120041007143. The next prime is 5120041007231. The reversal of 5120041007201 is 1027001400215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4642090011601 + 477950995600 = 2154551^2 + 691340^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5120041007201 is a prime.
It is not a weakly prime, because it can be changed into another prime (5120041007231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560020503600 + 2560020503601.
It is an arithmetic number, because the mean of its divisors is an integer number (2560020503601).
Almost surely, 25120041007201 is an apocalyptic number.
It is an amenable number.
5120041007201 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120041007201 is an equidigital number, since it uses as much as digits as its factorization.
5120041007201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 23.
Adding to 5120041007201 its reverse (1027001400215), we get a palindrome (6147042407416).
The spelling of 5120041007201 in words is "five trillion, one hundred twenty billion, forty-one million, seven thousand, two hundred one".
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