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5120045031503 = 6018519209703
BaseRepresentation
bin100101010000001101001…
…1101110010000001001111
3200010110201202000120112002
41022200122131302001033
51132341323012002003
614520041034102515
71035624326456543
oct112403235620117
920113652016462
105120045031503
1116a4442a394a6
126a837087aa3b
132b1a836b739c
14139b50a91a23
158d2b661ea88
hex4a81a77204f

5120045031503 has 4 divisors (see below), whose sum is σ = 5128564241808. Its totient is φ = 5111525821200.

The previous prime is 5120045031487. The next prime is 5120045031523. The reversal of 5120045031503 is 3051305400215.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5120045031503 - 24 = 5120045031487 is a prime.

It is a super-2 number, since 2×51200450315032 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5120045031523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4259604251 + ... + 4259605452.

It is an arithmetic number, because the mean of its divisors is an integer number (1282141060452).

Almost surely, 25120045031503 is an apocalyptic number.

5120045031503 is a deficient number, since it is larger than the sum of its proper divisors (8519210305).

5120045031503 is an equidigital number, since it uses as much as digits as its factorization.

5120045031503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8519210304.

The product of its (nonzero) digits is 9000, while the sum is 29.

The spelling of 5120045031503 in words is "five trillion, one hundred twenty billion, forty-five million, thirty-one thousand, five hundred three".

Divisors: 1 601 8519209703 5120045031503