Base | Representation |
---|---|
bin | 100101010000001101001… |
… | …1101110010000000111111 |
3 | 200010110201202000120111111 |
4 | 1022200122131302000333 |
5 | 1132341323012001422 |
6 | 14520041034102451 |
7 | 1035624326456521 |
oct | 112403235620077 |
9 | 20113652016444 |
10 | 5120045031487 |
11 | 16a4442a39491 |
12 | 6a837087aa27 |
13 | 2b1a836b7389 |
14 | 139b50a91a11 |
15 | 8d2b661ea77 |
hex | 4a81a77203f |
5120045031487 has 2 divisors, whose sum is σ = 5120045031488. Its totient is φ = 5120045031486.
The previous prime is 5120045031461. The next prime is 5120045031523. The reversal of 5120045031487 is 7841305400215.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5120045031487 is a prime.
It is a super-2 number, since 2×51200450314872 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5120045031407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560022515743 + 2560022515744.
It is an arithmetic number, because the mean of its divisors is an integer number (2560022515744).
Almost surely, 25120045031487 is an apocalyptic number.
5120045031487 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120045031487 is an equidigital number, since it uses as much as digits as its factorization.
5120045031487 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 134400, while the sum is 40.
The spelling of 5120045031487 in words is "five trillion, one hundred twenty billion, forty-five million, thirty-one thousand, four hundred eighty-seven".
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