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51201100033 is a prime number
BaseRepresentation
bin101111101011110100…
…101100100100000001
311220011021220101010021
4233223310230210001
51314324440200113
635304345133441
73461545112056
oct575364544401
9156137811107
1051201100033
111a794760306
129b0b18a281
134a9c85aac5
14269a06902d
1514ea04b48d
hexbebd2c901

51201100033 has 2 divisors, whose sum is σ = 51201100034. Its totient is φ = 51201100032.

The previous prime is 51201100019. The next prime is 51201100037. The reversal of 51201100033 is 33000110215.

51201100033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42844032144 + 8357067889 = 206988^2 + 91417^2 .

It is a cyclic number.

It is not a de Polignac number, because 51201100033 - 25 = 51201100001 is a prime.

It is not a weakly prime, because it can be changed into another prime (51201100037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25600550016 + 25600550017.

It is an arithmetic number, because the mean of its divisors is an integer number (25600550017).

Almost surely, 251201100033 is an apocalyptic number.

It is an amenable number.

51201100033 is a deficient number, since it is larger than the sum of its proper divisors (1).

51201100033 is an equidigital number, since it uses as much as digits as its factorization.

51201100033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 16.

Adding to 51201100033 its reverse (33000110215), we get a palindrome (84201210248).

The spelling of 51201100033 in words is "fifty-one billion, two hundred one million, one hundred thousand, thirty-three".