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512011967604947 is a prime number
BaseRepresentation
bin111010001101011000001001…
…1011100110010100011010011
32111010212212101100211001220122
41310122300103130302203103
51014102301002201324242
65012543014543100455
7212563433603101625
oct16432602334624323
92433785340731818
10512011967604947
11139163068652377
1249513423ba172b
1318c906a15b4c04
149061723622c15
153e2d9162e0ad2
hex1d1ac137328d3

512011967604947 has 2 divisors, whose sum is σ = 512011967604948. Its totient is φ = 512011967604946.

The previous prime is 512011967604881. The next prime is 512011967604971. The reversal of 512011967604947 is 749406769110215.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 512011967604947 - 218 = 512011967342803 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 512011967604947.

It is not a weakly prime, because it can be changed into another prime (512011967606947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256005983802473 + 256005983802474.

It is an arithmetic number, because the mean of its divisors is an integer number (256005983802474).

Almost surely, 2512011967604947 is an apocalyptic number.

512011967604947 is a deficient number, since it is larger than the sum of its proper divisors (1).

512011967604947 is an equidigital number, since it uses as much as digits as its factorization.

512011967604947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22861440, while the sum is 62.

The spelling of 512011967604947 in words is "five hundred twelve trillion, eleven billion, nine hundred sixty-seven million, six hundred four thousand, nine hundred forty-seven".