Search a number
-
+
5120141 = 13393857
BaseRepresentation
bin10011100010000010001101
3100122010111212
4103202002031
52302321031
6301424205
761343345
oct23420215
910563455
105120141
112987924
12186b065
1310a3690
14973d25
156b212b
hex4e208d

5120141 has 4 divisors (see below), whose sum is σ = 5514012. Its totient is φ = 4726272.

The previous prime is 5120131. The next prime is 5120183. The reversal of 5120141 is 1410215.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 372100 + 4748041 = 610^2 + 2179^2 .

It is a cyclic number.

It is not a de Polignac number, because 5120141 - 210 = 5119117 is a prime.

It is an Ulam number.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5120131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196916 + ... + 196941.

It is an arithmetic number, because the mean of its divisors is an integer number (1378503).

Almost surely, 25120141 is an apocalyptic number.

It is an amenable number.

5120141 is a deficient number, since it is larger than the sum of its proper divisors (393871).

5120141 is a wasteful number, since it uses less digits than its factorization.

5120141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 393870.

The product of its (nonzero) digits is 40, while the sum is 14.

The square root of 5120141 is about 2262.7728564750. The cubic root of 5120141 is about 172.3563573510.

Adding to 5120141 its reverse (1410215), we get a palindrome (6530356).

The spelling of 5120141 in words is "five million, one hundred twenty thousand, one hundred forty-one".

Divisors: 1 13 393857 5120141