Base | Representation |
---|---|
bin | 10011100010000010000011 |
3 | 100122010111111 |
4 | 103202002003 |
5 | 2302321011 |
6 | 301424151 |
7 | 61343332 |
oct | 23420203 |
9 | 10563444 |
10 | 5120131 |
11 | 2987915 |
12 | 186b057 |
13 | 10a3683 |
14 | 973d19 |
15 | 6b2121 |
hex | 4e2083 |
5120131 has 2 divisors, whose sum is σ = 5120132. Its totient is φ = 5120130.
The previous prime is 5120123. The next prime is 5120183. The reversal of 5120131 is 1310215.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5120131 - 23 = 5120123 is a prime.
It is a super-2 number, since 2×51201312 = 52431482914322, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5120231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560065 + 2560066.
It is an arithmetic number, because the mean of its divisors is an integer number (2560066).
Almost surely, 25120131 is an apocalyptic number.
5120131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120131 is an equidigital number, since it uses as much as digits as its factorization.
5120131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 13.
The square root of 5120131 is about 2262.7706467956. The cubic root of 5120131 is about 172.3562451428.
Adding to 5120131 its reverse (1310215), we get a palindrome (6430346).
The spelling of 5120131 in words is "five million, one hundred twenty thousand, one hundred thirty-one".
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