Base | Representation |
---|---|
bin | 101111101011110110… |
… | …101110110010011001 |
3 | 11220011022220110210211 |
4 | 233223312232302121 |
5 | 1314330104232213 |
6 | 35304404411121 |
7 | 3461552463136 |
oct | 575366566231 |
9 | 156138813724 |
10 | 51201633433 |
11 | 1a794a95035 |
12 | 9b0b3a6aa1 |
13 | 4a9c9b6822 |
14 | 269a16758d |
15 | 14ea10453d |
hex | bebdaec99 |
51201633433 has 2 divisors, whose sum is σ = 51201633434. Its totient is φ = 51201633432.
The previous prime is 51201633421. The next prime is 51201633449. The reversal of 51201633433 is 33433610215.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29040249744 + 22161383689 = 170412^2 + 148867^2 .
It is a cyclic number.
It is not a de Polignac number, because 51201633433 - 221 = 51199536281 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51201633395 and 51201633404.
It is not a weakly prime, because it can be changed into another prime (51201630433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25600816716 + 25600816717.
It is an arithmetic number, because the mean of its divisors is an integer number (25600816717).
Almost surely, 251201633433 is an apocalyptic number.
It is an amenable number.
51201633433 is a deficient number, since it is larger than the sum of its proper divisors (1).
51201633433 is an equidigital number, since it uses as much as digits as its factorization.
51201633433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 31.
The spelling of 51201633433 in words is "fifty-one billion, two hundred one million, six hundred thirty-three thousand, four hundred thirty-three".
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