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512030049181 = 773147149883
BaseRepresentation
bin1110111001101110101…
…11101000001110011101
31210221122020212112022121
413130313113220032131
531342114143033211
61031120124542541
751664403415130
oct7346727501635
91727566775277
10512030049181
11188172683502
12832999b1a51
13393905a3a81
141aad4c24217
15d4bbd3c271
hex77375e839d

512030049181 has 4 divisors (see below), whose sum is σ = 585177199072. Its totient is φ = 438882899292.

The previous prime is 512030049137. The next prime is 512030049227. The reversal of 512030049181 is 181940030215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 512030049181 - 229 = 511493178269 is a prime.

It is a super-2 number, since 2×5120300491812 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (512030044181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36573574935 + ... + 36573574948.

It is an arithmetic number, because the mean of its divisors is an integer number (146294299768).

Almost surely, 2512030049181 is an apocalyptic number.

It is an amenable number.

512030049181 is a deficient number, since it is larger than the sum of its proper divisors (73147149891).

512030049181 is an equidigital number, since it uses as much as digits as its factorization.

512030049181 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73147149890.

The product of its (nonzero) digits is 8640, while the sum is 34.

Adding to 512030049181 its reverse (181940030215), we get a palindrome (693970079396).

The spelling of 512030049181 in words is "five hundred twelve billion, thirty million, forty-nine thousand, one hundred eighty-one".

Divisors: 1 7 73147149883 512030049181