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51204001 is a prime number
BaseRepresentation
bin1100001101010…
…0111110100001
310120100102200111
43003110332201
5101102012001
65025251321
71161140542
oct303247641
9116312614
1051204001
11269a3362
1215193b41
13a7ba434
146b2c4c9
154766851
hex30d4fa1

51204001 has 2 divisors, whose sum is σ = 51204002. Its totient is φ = 51204000.

The previous prime is 51203981. The next prime is 51204007. The reversal of 51204001 is 10040215.

51204001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50069776 + 1134225 = 7076^2 + 1065^2 .

It is a cyclic number.

It is not a de Polignac number, because 51204001 - 25 = 51203969 is a prime.

It is not a weakly prime, because it can be changed into another prime (51204007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25602000 + 25602001.

It is an arithmetic number, because the mean of its divisors is an integer number (25602001).

Almost surely, 251204001 is an apocalyptic number.

It is an amenable number.

51204001 is a deficient number, since it is larger than the sum of its proper divisors (1).

51204001 is an equidigital number, since it uses as much as digits as its factorization.

51204001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40, while the sum is 13.

The square root of 51204001 is about 7155.6971009120. The cubic root of 51204001 is about 371.3367788313.

Adding to 51204001 its reverse (10040215), we get a palindrome (61244216).

The spelling of 51204001 in words is "fifty-one million, two hundred four thousand, one".