Base | Representation |
---|---|
bin | 100101010000011000111… |
… | …0010110000001110101001 |
3 | 200010111202000110102020202 |
4 | 1022200301302300032221 |
5 | 1132343123204431121 |
6 | 14520143534401545 |
7 | 1035640121212610 |
oct | 112406162601651 |
9 | 20114660412222 |
10 | 5120436405161 |
11 | 16a4623952300 |
12 | 6a845b9602b5 |
13 | 2b1b167c842c |
14 | 139b8aa4c877 |
15 | 8d2dab7c40b |
hex | 4a831cb03a9 |
5120436405161 has 24 divisors (see below), whose sum is σ = 6432449886912. Its totient is φ = 3989847391200.
The previous prime is 5120436405089. The next prime is 5120436405199. The reversal of 5120436405161 is 1615046340215.
It is not a de Polignac number, because 5120436405161 - 210 = 5120436404137 is a prime.
It is a super-3 number, since 3×51204364051613 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5120436401161) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 60103751 + ... + 60188883.
It is an arithmetic number, because the mean of its divisors is an integer number (268018745288).
Almost surely, 25120436405161 is an apocalyptic number.
It is an amenable number.
5120436405161 is a deficient number, since it is larger than the sum of its proper divisors (1312013481751).
5120436405161 is a wasteful number, since it uses less digits than its factorization.
5120436405161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156173 (or 156162 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 5120436405161 in words is "five trillion, one hundred twenty billion, four hundred thirty-six million, four hundred five thousand, one hundred sixty-one".
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