Base | Representation |
---|---|
bin | 101111101100011010… |
… | …100011101011011001 |
3 | 11220011222120121202211 |
4 | 233230122203223121 |
5 | 1314340010300423 |
6 | 35305341555121 |
7 | 3462025350133 |
oct | 575432435331 |
9 | 156158517684 |
10 | 51211025113 |
11 | 1a79a31a156 |
12 | 9b12575aa1 |
13 | 4aa1924531 |
14 | 269b4d0053 |
15 | 14ead5c10d |
hex | bec6a3ad9 |
51211025113 has 16 divisors (see below), whose sum is σ = 53600279040. Its totient is φ = 48877024000.
The previous prime is 51211025069. The next prime is 51211025179. The reversal of 51211025113 is 31152011215.
It is a cyclic number.
It is not a de Polignac number, because 51211025113 - 213 = 51211016921 is a prime.
It is a super-3 number, since 3×512110251133 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51211023113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5716788 + ... + 5725738.
It is an arithmetic number, because the mean of its divisors is an integer number (3350017440).
Almost surely, 251211025113 is an apocalyptic number.
It is an amenable number.
51211025113 is a deficient number, since it is larger than the sum of its proper divisors (2389253927).
51211025113 is a wasteful number, since it uses less digits than its factorization.
51211025113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12008.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 51211025113 its reverse (31152011215), we get a palindrome (82363036328).
It can be divided in two parts, 5121102 and 5113, that added together give a palindrome (5126215).
The spelling of 51211025113 in words is "fifty-one billion, two hundred eleven million, twenty-five thousand, one hundred thirteen".
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