Base | Representation |
---|---|
bin | 101111101100100000… |
… | …010100010011010111 |
3 | 11220012002102022221112 |
4 | 233230200110103113 |
5 | 1314340402104444 |
6 | 35305434205235 |
7 | 3462044236133 |
oct | 575440242327 |
9 | 156162368845 |
10 | 51212534999 |
11 | 1a7a016059a |
12 | 9b12b8381b |
13 | 4aa2032862 |
14 | 269b7a43c3 |
15 | 14eb05969e |
hex | bec8144d7 |
51212534999 has 4 divisors (see below), whose sum is σ = 51402916440. Its totient is φ = 51022153560.
The previous prime is 51212534993. The next prime is 51212535013. The reversal of 51212534999 is 99943521215.
51212534999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 99943521215 = 5 ⋅19988704243.
It is a cyclic number.
It is not a de Polignac number, because 51212534999 - 212 = 51212530903 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51212534993) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95190317 + ... + 95190854.
It is an arithmetic number, because the mean of its divisors is an integer number (12850729110).
Almost surely, 251212534999 is an apocalyptic number.
51212534999 is a deficient number, since it is larger than the sum of its proper divisors (190381441).
51212534999 is a wasteful number, since it uses less digits than its factorization.
51212534999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190381440.
The product of its digits is 874800, while the sum is 50.
The spelling of 51212534999 in words is "fifty-one billion, two hundred twelve million, five hundred thirty-four thousand, nine hundred ninety-nine".
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