Base | Representation |
---|---|
bin | 100101010000110101010… |
… | …1110001101000010110111 |
3 | 200010121012120122221222011 |
4 | 1022201222232031002313 |
5 | 1132402102211420113 |
6 | 14520422413545051 |
7 | 1036002566414056 |
oct | 112415256150267 |
9 | 20117176587864 |
10 | 5121391513783 |
11 | 16a4a73aa4576 |
12 | 6a86877a5187 |
13 | 2b1c3964856c |
14 | 139c3b83239d |
15 | 8d34494263d |
hex | 4a86ab8d0b7 |
5121391513783 has 8 divisors (see below), whose sum is σ = 5371718300352. Its totient is φ = 4876954769376.
The previous prime is 5121391513673. The next prime is 5121391513787. The reversal of 5121391513783 is 3873151931215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5121391513783 - 225 = 5121357959351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5121391513787) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1472508760 + ... + 1472512237.
It is an arithmetic number, because the mean of its divisors is an integer number (671464787544).
Almost surely, 25121391513783 is an apocalyptic number.
5121391513783 is a deficient number, since it is larger than the sum of its proper divisors (250326786569).
5121391513783 is a wasteful number, since it uses less digits than its factorization.
5121391513783 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2945021081.
The product of its digits is 680400, while the sum is 49.
The spelling of 5121391513783 in words is "five trillion, one hundred twenty-one billion, three hundred ninety-one million, five hundred thirteen thousand, seven hundred eighty-three".
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