Base | Representation |
---|---|
bin | 111010001110010101010111… |
… | …1010010011011001111100101 |
3 | 2111011100102201021200020111120 |
4 | 1310130222233102123033211 |
5 | 1014111424221333340423 |
6 | 5013123235543124153 |
7 | 212606066440603041 |
oct | 16434525722331745 |
9 | 2434312637606446 |
10 | 512143431152613 |
11 | 13920389a374527 |
12 | 495349b2a43659 |
13 | 18c9cbc2757b80 |
14 | 9067c35223021 |
15 | 3e3205c89cee3 |
hex | 1d1caaf49b3e5 |
512143431152613 has 32 divisors (see below), whose sum is σ = 735576442441344. Its totient is φ = 315083337821952.
The previous prime is 512143431152543. The next prime is 512143431152651. The reversal of 512143431152613 is 316251134341215.
It is not a de Polignac number, because 512143431152613 - 28 = 512143431152357 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (512143431157613) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3709690495 + ... + 3709828547.
It is an arithmetic number, because the mean of its divisors is an integer number (22986763826292).
Almost surely, 2512143431152613 is an apocalyptic number.
It is an amenable number.
512143431152613 is a deficient number, since it is larger than the sum of its proper divisors (223433011288731).
512143431152613 is a wasteful number, since it uses less digits than its factorization.
512143431152613 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162085.
The product of its digits is 259200, while the sum is 42.
Adding to 512143431152613 its reverse (316251134341215), we get a palindrome (828394565493828).
The spelling of 512143431152613 in words is "five hundred twelve trillion, one hundred forty-three billion, four hundred thirty-one million, one hundred fifty-two thousand, six hundred thirteen".
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