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5121771145433 is a prime number
BaseRepresentation
bin100101010001000000101…
…0110011000100011011001
3200010122012001000020200122
41022202001112120203121
51132403341403123213
614520524214443025
71036015156263635
oct112420126304331
920118161006618
105121771145433
1116a5149318438
126a8772963475
132b1c9a1a7b87
14139c76013dc5
158d367e30d08
hex4a8815988d9

5121771145433 has 2 divisors, whose sum is σ = 5121771145434. Its totient is φ = 5121771145432.

The previous prime is 5121771145427. The next prime is 5121771145493. The reversal of 5121771145433 is 3345411771215.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5121770975689 + 169744 = 2263133^2 + 412^2 .

It is a cyclic number.

It is not a de Polignac number, because 5121771145433 - 24 = 5121771145417 is a prime.

It is not a weakly prime, because it can be changed into another prime (5121771145493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560885572716 + 2560885572717.

It is an arithmetic number, because the mean of its divisors is an integer number (2560885572717).

Almost surely, 25121771145433 is an apocalyptic number.

It is an amenable number.

5121771145433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5121771145433 is an equidigital number, since it uses as much as digits as its factorization.

5121771145433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 352800, while the sum is 44.

The spelling of 5121771145433 in words is "five trillion, one hundred twenty-one billion, seven hundred seventy-one million, one hundred forty-five thousand, four hundred thirty-three".