Base | Representation |
---|---|
bin | 100101010001000000101… |
… | …0110011000100011011001 |
3 | 200010122012001000020200122 |
4 | 1022202001112120203121 |
5 | 1132403341403123213 |
6 | 14520524214443025 |
7 | 1036015156263635 |
oct | 112420126304331 |
9 | 20118161006618 |
10 | 5121771145433 |
11 | 16a5149318438 |
12 | 6a8772963475 |
13 | 2b1c9a1a7b87 |
14 | 139c76013dc5 |
15 | 8d367e30d08 |
hex | 4a8815988d9 |
5121771145433 has 2 divisors, whose sum is σ = 5121771145434. Its totient is φ = 5121771145432.
The previous prime is 5121771145427. The next prime is 5121771145493. The reversal of 5121771145433 is 3345411771215.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5121770975689 + 169744 = 2263133^2 + 412^2 .
It is a cyclic number.
It is not a de Polignac number, because 5121771145433 - 24 = 5121771145417 is a prime.
It is not a weakly prime, because it can be changed into another prime (5121771145493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560885572716 + 2560885572717.
It is an arithmetic number, because the mean of its divisors is an integer number (2560885572717).
Almost surely, 25121771145433 is an apocalyptic number.
It is an amenable number.
5121771145433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5121771145433 is an equidigital number, since it uses as much as digits as its factorization.
5121771145433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 352800, while the sum is 44.
The spelling of 5121771145433 in words is "five trillion, one hundred twenty-one billion, seven hundred seventy-one million, one hundred forty-five thousand, four hundred thirty-three".
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