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5122140352019 is a prime number
BaseRepresentation
bin100101010001001011101…
…0110110010111000010011
3200010200010202201212220122
41022202113112302320103
51132410120412231034
614521025004100455
71036030261423655
oct112422726627023
920120122655818
105122140352019
1116a5318770849
126a885653472b
132b2028827302
14139cad0806d5
158d38a56062e
hex4a8975b2e13

5122140352019 has 2 divisors, whose sum is σ = 5122140352020. Its totient is φ = 5122140352018.

The previous prime is 5122140351961. The next prime is 5122140352037. The reversal of 5122140352019 is 9102530412215.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5122140352019 - 28 = 5122140351763 is a prime.

It is a super-2 number, since 2×51221403520192 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5122140352019.

It is not a weakly prime, because it can be changed into another prime (5122140358019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561070176009 + 2561070176010.

It is an arithmetic number, because the mean of its divisors is an integer number (2561070176010).

Almost surely, 25122140352019 is an apocalyptic number.

5122140352019 is a deficient number, since it is larger than the sum of its proper divisors (1).

5122140352019 is an equidigital number, since it uses as much as digits as its factorization.

5122140352019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 5122140352019 in words is "five trillion, one hundred twenty-two billion, one hundred forty million, three hundred fifty-two thousand, nineteen".