Base | Representation |
---|---|
bin | 111010001110111011011010… |
… | …0111010110101101001110101 |
3 | 2111011122020121000111021102220 |
4 | 1310131312310322311221311 |
5 | 1014114244031240330003 |
6 | 5013224550505152553 |
7 | 212615021141464221 |
oct | 16435666472655165 |
9 | 2434566530437386 |
10 | 512225130011253 |
11 | 13923550423420a |
12 | 495487b378b759 |
13 | 18ca7812829889 |
14 | 906bb85867781 |
15 | 3e34240097353 |
hex | 1d1ddb4eb5a75 |
512225130011253 has 32 divisors (see below), whose sum is σ = 711577246808064. Its totient is φ = 327470230080000.
The previous prime is 512225130011219. The next prime is 512225130011261. The reversal of 512225130011253 is 352110031522215.
It is not a de Polignac number, because 512225130011253 - 237 = 512087691057781 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (512225130011213) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12168178 + ... + 34242003.
It is an arithmetic number, because the mean of its divisors is an integer number (22236788962752).
Almost surely, 2512225130011253 is an apocalyptic number.
It is an amenable number.
512225130011253 is a deficient number, since it is larger than the sum of its proper divisors (199352116796811).
512225130011253 is a wasteful number, since it uses less digits than its factorization.
512225130011253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46411757.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 512225130011253 its reverse (352110031522215), we get a palindrome (864335161533468).
The spelling of 512225130011253 in words is "five hundred twelve trillion, two hundred twenty-five billion, one hundred thirty million, eleven thousand, two hundred fifty-three".
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