Base | Representation |
---|---|
bin | 10111010010110110110011… |
… | …01101010100111010111011 |
3 | 20201101002210110121202022021 |
4 | 23221123121231110322323 |
5 | 23203234141210311024 |
6 | 300540345552535311 |
7 | 13534625654042056 |
oct | 1351333155247273 |
9 | 221332713552267 |
10 | 51225432510139 |
11 | 1535a6472314a8 |
12 | 58b39b9851537 |
13 | 22776cb029144 |
14 | c91477703a9d |
15 | 5dc7574a3de4 |
hex | 2e96d9b54ebb |
51225432510139 has 2 divisors, whose sum is σ = 51225432510140. Its totient is φ = 51225432510138.
The previous prime is 51225432510103. The next prime is 51225432510157. The reversal of 51225432510139 is 93101523452215.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51225432510139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51225432510095 and 51225432510104.
It is not a weakly prime, because it can be changed into another prime (51225432510839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25612716255069 + 25612716255070.
It is an arithmetic number, because the mean of its divisors is an integer number (25612716255070).
Almost surely, 251225432510139 is an apocalyptic number.
51225432510139 is a deficient number, since it is larger than the sum of its proper divisors (1).
51225432510139 is an equidigital number, since it uses as much as digits as its factorization.
51225432510139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 43.
The spelling of 51225432510139 in words is "fifty-one trillion, two hundred twenty-five billion, four hundred thirty-two million, five hundred ten thousand, one hundred thirty-nine".
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