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5123201251335 = 352997712054733
BaseRepresentation
bin100101010001101011010…
…0101110011100000000111
3200010202212201000011011220
41022203112211303200013
51132414304010020320
614521322142531423
71036065463055616
oct112432645634007
920122781004156
105123201251335
1116a58125aa142
126a8ab1896b73
132b216756789b
14139d6dd2187d
158d3ed770e40
hex4a8d6973807

5123201251335 has 32 divisors (see below), whose sum is σ = 8488461493440. Its totient is φ = 2635453728768.

The previous prime is 5123201251319. The next prime is 5123201251349. The reversal of 5123201251335 is 5331521023215.

It is not a de Polignac number, because 5123201251335 - 24 = 5123201251319 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5123201251296 and 5123201251305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5602372 + ... + 6452361.

It is an arithmetic number, because the mean of its divisors is an integer number (265264421670).

Almost surely, 25123201251335 is an apocalyptic number.

5123201251335 is a deficient number, since it is larger than the sum of its proper divisors (3365260242105).

5123201251335 is a wasteful number, since it uses less digits than its factorization.

5123201251335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12055747.

The product of its (nonzero) digits is 27000, while the sum is 33.

The spelling of 5123201251335 in words is "five trillion, one hundred twenty-three billion, two hundred one million, two hundred fifty-one thousand, three hundred thirty-five".

Divisors: 1 3 5 15 29 87 145 435 977 2931 4885 14655 28333 84999 141665 424995 12054733 36164199 60273665 180820995 349587257 1048761771 1747936285 5243808855 11777474141 35332422423 58887370705 176662112115 341546750089 1024640250267 1707733750445 5123201251335