Base | Representation |
---|---|
bin | 100101010001101011010… |
… | …0101110011100000000111 |
3 | 200010202212201000011011220 |
4 | 1022203112211303200013 |
5 | 1132414304010020320 |
6 | 14521322142531423 |
7 | 1036065463055616 |
oct | 112432645634007 |
9 | 20122781004156 |
10 | 5123201251335 |
11 | 16a58125aa142 |
12 | 6a8ab1896b73 |
13 | 2b216756789b |
14 | 139d6dd2187d |
15 | 8d3ed770e40 |
hex | 4a8d6973807 |
5123201251335 has 32 divisors (see below), whose sum is σ = 8488461493440. Its totient is φ = 2635453728768.
The previous prime is 5123201251319. The next prime is 5123201251349. The reversal of 5123201251335 is 5331521023215.
It is not a de Polignac number, because 5123201251335 - 24 = 5123201251319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5123201251296 and 5123201251305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5602372 + ... + 6452361.
It is an arithmetic number, because the mean of its divisors is an integer number (265264421670).
Almost surely, 25123201251335 is an apocalyptic number.
5123201251335 is a deficient number, since it is larger than the sum of its proper divisors (3365260242105).
5123201251335 is a wasteful number, since it uses less digits than its factorization.
5123201251335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12055747.
The product of its (nonzero) digits is 27000, while the sum is 33.
The spelling of 5123201251335 in words is "five trillion, one hundred twenty-three billion, two hundred one million, two hundred fifty-one thousand, three hundred thirty-five".
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