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51234013641311 = 212846324070897
BaseRepresentation
bin10111010011000110110010…
…01011101111101001011111
320201101220221111112101022022
423221203121023233221133
523203404224443010221
6300544325252210355
713535351422333154
oct1351433113575137
9221356844471268
1051234013641311
111536325003a346
1258b55b36099bb
132278467a8c557
14c91a4d24222b
155dcaaa9e14ab
hex2e98d92efa5f

51234013641311 has 4 divisors (see below), whose sum is σ = 51234039840672. Its totient is φ = 51233987441952.

The previous prime is 51234013641289. The next prime is 51234013641313. The reversal of 51234013641311 is 11314631043215.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51234013641311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51234013641313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9906986 + ... + 14163911.

It is an arithmetic number, because the mean of its divisors is an integer number (12808509960168).

Almost surely, 251234013641311 is an apocalyptic number.

51234013641311 is a deficient number, since it is larger than the sum of its proper divisors (26199361).

51234013641311 is a wasteful number, since it uses less digits than its factorization.

51234013641311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26199360.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 51234013641311 its reverse (11314631043215), we get a palindrome (62548644684526).

The spelling of 51234013641311 in words is "fifty-one trillion, two hundred thirty-four billion, thirteen million, six hundred forty-one thousand, three hundred eleven".

Divisors: 1 2128463 24070897 51234013641311