Base | Representation |
---|---|
bin | 10111010011000111001001… |
… | …11010000000111100000011 |
3 | 20201101221110012121200221001 |
4 | 23221203210322000330003 |
5 | 23203410130320221011 |
6 | 300544400555512431 |
7 | 13535356331145616 |
oct | 1351434472007403 |
9 | 221357405550831 |
10 | 51234210320131 |
11 | 15363341064023 |
12 | 58b5649458717 |
13 | 2278499752c57 |
14 | c91a6b3dc17d |
15 | 5dcabcde17c1 |
hex | 2e98e4e80f03 |
51234210320131 has 2 divisors, whose sum is σ = 51234210320132. Its totient is φ = 51234210320130.
The previous prime is 51234210320119. The next prime is 51234210320141. The reversal of 51234210320131 is 13102301243215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51234210320131 - 225 = 51234176765699 is a prime.
It is a super-2 number, since 2×512342103201312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 51234210320131.
It is not a weakly prime, because it can be changed into another prime (51234210320141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25617105160065 + 25617105160066.
It is an arithmetic number, because the mean of its divisors is an integer number (25617105160066).
Almost surely, 251234210320131 is an apocalyptic number.
51234210320131 is a deficient number, since it is larger than the sum of its proper divisors (1).
51234210320131 is an equidigital number, since it uses as much as digits as its factorization.
51234210320131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 51234210320131 its reverse (13102301243215), we get a palindrome (64336511563346).
The spelling of 51234210320131 in words is "fifty-one trillion, two hundred thirty-four billion, two hundred ten million, three hundred twenty thousand, one hundred thirty-one".
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