Base | Representation |
---|---|
bin | 100101010010000011001… |
… | …1101010001111110000111 |
3 | 200010211221200010102200120 |
4 | 1022210012131101332013 |
5 | 1132422430101320312 |
6 | 14521533551313023 |
7 | 1036124414055210 |
oct | 112440635217607 |
9 | 20124850112616 |
10 | 5124004323207 |
11 | 16a6094948a00 |
12 | 6a909681b773 |
13 | 2b2264a54a43 |
14 | 13a00884a407 |
15 | 8d44900328c |
hex | 4a906751f87 |
5124004323207 has 96 divisors (see below), whose sum is σ = 8629102648320. Its totient is φ = 2647350604800.
The previous prime is 5124004323161. The next prime is 5124004323223. The reversal of 5124004323207 is 7023234004215.
It is not a de Polignac number, because 5124004323207 - 230 = 5122930581383 is a prime.
It is a super-3 number, since 3×51240043232073 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5124004325207) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 513782673 + ... + 513792645.
It is an arithmetic number, because the mean of its divisors is an integer number (89886485920).
Almost surely, 25124004323207 is an apocalyptic number.
5124004323207 is a deficient number, since it is larger than the sum of its proper divisors (3505098325113).
5124004323207 is a wasteful number, since it uses less digits than its factorization.
5124004323207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11085 (or 11074 counting only the distinct ones).
The product of its (nonzero) digits is 40320, while the sum is 33.
The spelling of 5124004323207 in words is "five trillion, one hundred twenty-four billion, four million, three hundred twenty-three thousand, two hundred seven".
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