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51240433 is a prime number
BaseRepresentation
bin1100001101110…
…1110111110001
310120102021122211
43003131313301
5101104143213
65030132121
71161352006
oct303356761
9116367584
1051240433
1126a18772
12151b1041
13a800baa
146b3b8ad
15477253d
hex30dddf1

51240433 has 2 divisors, whose sum is σ = 51240434. Its totient is φ = 51240432.

The previous prime is 51240407. The next prime is 51240437. The reversal of 51240433 is 33404215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26708224 + 24532209 = 5168^2 + 4953^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51240433 is a prime.

It is not a weakly prime, because it can be changed into another prime (51240437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25620216 + 25620217.

It is an arithmetic number, because the mean of its divisors is an integer number (25620217).

Almost surely, 251240433 is an apocalyptic number.

It is an amenable number.

51240433 is a deficient number, since it is larger than the sum of its proper divisors (1).

51240433 is an equidigital number, since it uses as much as digits as its factorization.

51240433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 51240433 is about 7158.2423121881. The cubic root of 51240433 is about 371.4248275123.

Adding to 51240433 its reverse (33404215), we get a palindrome (84644648).

The spelling of 51240433 in words is "fifty-one million, two hundred forty thousand, four hundred thirty-three".