Base | Representation |
---|---|
bin | 10111010011010100100101… |
… | …11001101011000001000001 |
3 | 20201102122001222020121122121 |
4 | 23221222102321223001001 |
5 | 23204014414123330332 |
6 | 300551552503204241 |
7 | 13536033160122364 |
oct | 1351522271530101 |
9 | 221378058217577 |
10 | 51241424433217 |
11 | 1536640325aa57 |
12 | 58b6b21446681 |
13 | 2279079214c15 |
14 | c921535720db |
15 | 5dcd91401797 |
hex | 2e9a92e6b041 |
51241424433217 has 2 divisors, whose sum is σ = 51241424433218. Its totient is φ = 51241424433216.
The previous prime is 51241424433191. The next prime is 51241424433289. The reversal of 51241424433217 is 71233442414215.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 47000361973761 + 4241062459456 = 6855681^2 + 2059384^2 .
It is a cyclic number.
It is not a de Polignac number, because 51241424433217 - 219 = 51241423908929 is a prime.
It is not a weakly prime, because it can be changed into another prime (51241424233217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25620712216608 + 25620712216609.
It is an arithmetic number, because the mean of its divisors is an integer number (25620712216609).
Almost surely, 251241424433217 is an apocalyptic number.
It is an amenable number.
51241424433217 is a deficient number, since it is larger than the sum of its proper divisors (1).
51241424433217 is an equidigital number, since it uses as much as digits as its factorization.
51241424433217 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 645120, while the sum is 43.
The spelling of 51241424433217 in words is "fifty-one trillion, two hundred forty-one billion, four hundred twenty-four million, four hundred thirty-three thousand, two hundred seventeen".
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