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5124305000081 is a prime number
BaseRepresentation
bin100101010010001100001…
…1000010001011010010001
3200010212201121220101211002
41022210120120101122101
51132424034040000311
614522023452031345
71036135024554161
oct112443030213221
920125647811732
105124305000081
1116a6229644993
126a915b462555
132b22b212b957
1413a0367585a1
158d4655e793b
hex4a918611691

5124305000081 has 2 divisors, whose sum is σ = 5124305000082. Its totient is φ = 5124305000080.

The previous prime is 5124305000057. The next prime is 5124305000117. The reversal of 5124305000081 is 1800005034215.

5124305000081 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3816005971600 + 1308299028481 = 1953460^2 + 1143809^2 .

It is a cyclic number.

It is not a de Polignac number, because 5124305000081 - 214 = 5124304983697 is a prime.

It is a super-2 number, since 2×51243050000812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5124305000681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562152500040 + 2562152500041.

It is an arithmetic number, because the mean of its divisors is an integer number (2562152500041).

Almost surely, 25124305000081 is an apocalyptic number.

It is an amenable number.

5124305000081 is a deficient number, since it is larger than the sum of its proper divisors (1).

5124305000081 is an equidigital number, since it uses as much as digits as its factorization.

5124305000081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 29.

The spelling of 5124305000081 in words is "five trillion, one hundred twenty-four billion, three hundred five million, eighty-one", and thus it is an aban number.