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5124401 is a prime number
BaseRepresentation
bin10011100011000100110001
3100122100100122
4103203010301
52302440101
6301500025
761361642
oct23430461
910570318
105124401
112990047
121871615
1310a55b9
149756c9
156b351b
hex4e3131

5124401 has 2 divisors, whose sum is σ = 5124402. Its totient is φ = 5124400.

The previous prime is 5124397. The next prime is 5124407. The reversal of 5124401 is 1044215.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2640625 + 2483776 = 1625^2 + 1576^2 .

It is a cyclic number.

It is not a de Polignac number, because 5124401 - 22 = 5124397 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5124401.

It is not a weakly prime, because it can be changed into another prime (5124407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562200 + 2562201.

It is an arithmetic number, because the mean of its divisors is an integer number (2562201).

Almost surely, 25124401 is an apocalyptic number.

It is an amenable number.

5124401 is a deficient number, since it is larger than the sum of its proper divisors (1).

5124401 is an equidigital number, since it uses as much as digits as its factorization.

5124401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 160, while the sum is 17.

The square root of 5124401 is about 2263.7139837002. The cubic root of 5124401 is about 172.4041447424.

Adding to 5124401 its reverse (1044215), we get a palindrome (6168616).

It can be divided in two parts, 512 and 4401, that added together give a cube (4913 = 173).

The spelling of 5124401 in words is "five million, one hundred twenty-four thousand, four hundred one".