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512441113 is a prime number
BaseRepresentation
bin11110100010110…
…011101100011001
31022201020201001111
4132202303230121
52022141103423
6122503220321
715461451262
oct3642635431
91281221044
10512441113
11243294658
121237476a1
138221cac2
144c0b3969
152eec460d
hex1e8b3b19

512441113 has 2 divisors, whose sum is σ = 512441114. Its totient is φ = 512441112.

The previous prime is 512441099. The next prime is 512441131. The reversal of 512441113 is 311144215.

Together with next prime (512441131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 421563024 + 90878089 = 20532^2 + 9533^2 .

It is a cyclic number.

It is not a de Polignac number, because 512441113 - 29 = 512440601 is a prime.

It is not a weakly prime, because it can be changed into another prime (512441213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256220556 + 256220557.

It is an arithmetic number, because the mean of its divisors is an integer number (256220557).

Almost surely, 2512441113 is an apocalyptic number.

It is an amenable number.

512441113 is a deficient number, since it is larger than the sum of its proper divisors (1).

512441113 is an equidigital number, since it uses as much as digits as its factorization.

512441113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 480, while the sum is 22.

The square root of 512441113 is about 22637.1622117261. The cubic root of 512441113 is about 800.2296804065.

Adding to 512441113 its reverse (311144215), we get a palindrome (823585328).

The spelling of 512441113 in words is "five hundred twelve million, four hundred forty-one thousand, one hundred thirteen".