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512451210006553 is a prime number
BaseRepresentation
bin111010010000100100101100…
…0010101100101000000011001
32111012102212010220212222210011
41310201021120111211000121
51014132000034230202203
65013520500320121521
7212640243462650026
oct16441113025450031
92435385126788704
10512451210006553
11139312379522934
12495845894662a1
1318cc2c3204a61c
149078ab150454d
153e3a072e2276d
hex1d21258565019

512451210006553 has 2 divisors, whose sum is σ = 512451210006554. Its totient is φ = 512451210006552.

The previous prime is 512451210006509. The next prime is 512451210006557. The reversal of 512451210006553 is 355600012154215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 481642848927769 + 30808361078784 = 21946363^2 + 5550528^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-512451210006553 is a prime.

It is not a weakly prime, because it can be changed into another prime (512451210006557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256225605003276 + 256225605003277.

It is an arithmetic number, because the mean of its divisors is an integer number (256225605003277).

Almost surely, 2512451210006553 is an apocalyptic number.

It is an amenable number.

512451210006553 is a deficient number, since it is larger than the sum of its proper divisors (1).

512451210006553 is an equidigital number, since it uses as much as digits as its factorization.

512451210006553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180000, while the sum is 40.

The spelling of 512451210006553 in words is "five hundred twelve trillion, four hundred fifty-one billion, two hundred ten million, six thousand, five hundred fifty-three".