Base | Representation |
---|---|
bin | 100101010010100101001… |
… | …1010000100111111100111 |
3 | 200010221220010020222221001 |
4 | 1022211022122010333213 |
5 | 1132432243422144221 |
6 | 14522243033534131 |
7 | 1036164566023561 |
oct | 112451232047747 |
9 | 20127803228831 |
10 | 5125144334311 |
11 | 16a661a401141 |
12 | 6a9354574347 |
13 | 2b23b6ca4321 |
14 | 13a0b6002331 |
15 | 8d4b413e391 |
hex | 4a94a684fe7 |
5125144334311 has 4 divisors (see below), whose sum is σ = 5125295681824. Its totient is φ = 5124992986800.
The previous prime is 5125144334291. The next prime is 5125144334327. The reversal of 5125144334311 is 1134334415215.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5125144334311 - 219 = 5125143810023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5125144334371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75622950 + ... + 75690691.
It is an arithmetic number, because the mean of its divisors is an integer number (1281323920456).
Almost surely, 25125144334311 is an apocalyptic number.
5125144334311 is a deficient number, since it is larger than the sum of its proper divisors (151347513).
5125144334311 is a wasteful number, since it uses less digits than its factorization.
5125144334311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151347512.
The product of its digits is 86400, while the sum is 37.
Adding to 5125144334311 its reverse (1134334415215), we get a palindrome (6259478749526).
The spelling of 5125144334311 in words is "five trillion, one hundred twenty-five billion, one hundred forty-four million, three hundred thirty-four thousand, three hundred eleven".
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