Base | Representation |
---|---|
bin | 100101010010101110011… |
… | …1101001110111111110011 |
3 | 200010222200210211220011111 |
4 | 1022211130331032333303 |
5 | 1132433413104241321 |
6 | 14522333552054151 |
7 | 1036205365154446 |
oct | 112453475167763 |
9 | 20128623756144 |
10 | 5125455540211 |
11 | 16a676a0397a6 |
12 | 6a9420834357 |
13 | 2b24365c6826 |
14 | 13a10549165d |
15 | 8d4d16135e1 |
hex | 4a95cf4eff3 |
5125455540211 has 2 divisors, whose sum is σ = 5125455540212. Its totient is φ = 5125455540210.
The previous prime is 5125455540197. The next prime is 5125455540269. The reversal of 5125455540211 is 1120455545215.
5125455540211 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5125455540211 - 27 = 5125455540083 is a prime.
It is not a weakly prime, because it can be changed into another prime (5125455540011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2562727770105 + 2562727770106.
It is an arithmetic number, because the mean of its divisors is an integer number (2562727770106).
Almost surely, 25125455540211 is an apocalyptic number.
5125455540211 is a deficient number, since it is larger than the sum of its proper divisors (1).
5125455540211 is an equidigital number, since it uses as much as digits as its factorization.
5125455540211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 200000, while the sum is 40.
The spelling of 5125455540211 in words is "five trillion, one hundred twenty-five billion, four hundred fifty-five million, five hundred forty thousand, two hundred eleven".
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