Base | Representation |
---|---|
bin | 101111110001001101… |
… | …100001011100001001 |
3 | 11220101120222212112122 |
4 | 233301031201130021 |
5 | 1320021110303103 |
6 | 35321334421025 |
7 | 3464023335554 |
oct | 576115413411 |
9 | 156346885478 |
10 | 51291494153 |
11 | 1a830790799 |
12 | 9b35501775 |
13 | 4ab54ba253 |
14 | 26a807969b |
15 | 1502e54b38 |
hex | bf1361709 |
51291494153 has 2 divisors, whose sum is σ = 51291494154. Its totient is φ = 51291494152.
The previous prime is 51291494077. The next prime is 51291494179. The reversal of 51291494153 is 35149419215.
51291494153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51271450624 + 20043529 = 226432^2 + 4477^2 .
It is a cyclic number.
It is not a de Polignac number, because 51291494153 - 210 = 51291493129 is a prime.
It is not a weakly prime, because it can be changed into another prime (51291494183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25645747076 + 25645747077.
It is an arithmetic number, because the mean of its divisors is an integer number (25645747077).
Almost surely, 251291494153 is an apocalyptic number.
It is an amenable number.
51291494153 is a deficient number, since it is larger than the sum of its proper divisors (1).
51291494153 is an equidigital number, since it uses as much as digits as its factorization.
51291494153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 194400, while the sum is 44.
The spelling of 51291494153 in words is "fifty-one billion, two hundred ninety-one million, four hundred ninety-four thousand, one hundred fifty-three".
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