Base | Representation |
---|---|
bin | 1001100011011110… |
… | …01111001000101011 |
3 | 111020110221020010211 |
4 | 10301233033020223 |
5 | 41001113334033 |
6 | 2204553321551 |
7 | 241053316015 |
oct | 46157171053 |
9 | 14213836124 |
10 | 5129433643 |
11 | 21a2482464 |
12 | bb1a062b7 |
13 | 639909649 |
14 | 3693551b5 |
15 | 2004c22cd |
hex | 131bcf22b |
5129433643 has 2 divisors, whose sum is σ = 5129433644. Its totient is φ = 5129433642.
The previous prime is 5129433587. The next prime is 5129433677. The reversal of 5129433643 is 3463349215.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5129433643 - 29 = 5129433131 is a prime.
It is a super-2 number, since 2×51294336432 = 52622178995880502898, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5129433596 and 5129433605.
It is not a weakly prime, because it can be changed into another prime (5129463643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2564716821 + 2564716822.
It is an arithmetic number, because the mean of its divisors is an integer number (2564716822).
Almost surely, 25129433643 is an apocalyptic number.
5129433643 is a deficient number, since it is larger than the sum of its proper divisors (1).
5129433643 is an equidigital number, since it uses as much as digits as its factorization.
5129433643 is an evil number, because the sum of its binary digits is even.
The product of its digits is 233280, while the sum is 40.
The square root of 5129433643 is about 71620.0645280357. The cubic root of 5129433643 is about 1724.6056529636.
The spelling of 5129433643 in words is "five billion, one hundred twenty-nine million, four hundred thirty-three thousand, six hundred forty-three".
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