513000403 has 2 divisors, whose sum is σ = 513000404. Its totient is φ = 513000402.

The previous prime is 513000337. The next prime is 513000413. The reversal of 513000403 is 304000315.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 513000403 - 2⁹ = 512999891 is a prime.

It is not a weakly prime, because it can be changed into another prime (513000413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256500201 + 256500202.

It is an arithmetic number, because the mean of its divisors is an integer number (256500202).

Almost surely, 2^513000403 is an apocalyptic number.

513000403 is a deficient number, since it is larger than the sum of its proper divisors (1).

513000403 is an equidigital number, since it uses as much as digits as its factorization.

513000403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 16.

The square root of 513000403 is about 22649.5122022528. The cubic root of 513000403 is about 800.5207042395.

Adding to 513000403 its reverse (304000315), we get a palindrome (817000718).

The spelling of 513000403 in words is "five hundred thirteen million, four hundred three", and thus it is an aban number.