513003413301 has 4 divisors (see below), whose sum is σ = 684004551072. Its totient is φ = 342002275532.

The previous prime is 513003413269. The next prime is 513003413303. The reversal of 513003413301 is 103314300315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 513003413301 - 2⁵ = 513003413269 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (513003413303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85500568881 + ... + 85500568886.

It is an arithmetic number, because the mean of its divisors is an integer number (171001137768).

Almost surely, 2^513003413301 is an apocalyptic number.

It is an amenable number.

513003413301 is a deficient number, since it is larger than the sum of its proper divisors (171001137771).

513003413301 is a wasteful number, since it uses less digits than its factorization.

513003413301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171001137770.

The product of its (nonzero) digits is 1620, while the sum is 24.

Adding to 513003413301 its reverse (103314300315), we get a palindrome (616317713616).

The spelling of 513003413301 in words is "five hundred thirteen billion, three million, four hundred thirteen thousand, three hundred one".