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513004351331 is a prime number
BaseRepresentation
bin1110111011100010111…
…00010010111101100011
31211001011011012012121102
413131301130102331203
531401113103220311
61031400531345015
752030504016153
oct7356134227543
91731134165542
10513004351331
1118862264509a
128351015216b
13394b73b4214
141ab883a2763
15d52764443b
hex7771712f63

513004351331 has 2 divisors, whose sum is σ = 513004351332. Its totient is φ = 513004351330.

The previous prime is 513004351313. The next prime is 513004351369. The reversal of 513004351331 is 133153400315.

Together with previous prime (513004351313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 513004351331 - 26 = 513004351267 is a prime.

It is a super-2 number, since 2×5130043513312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 513004351294 and 513004351303.

It is not a weakly prime, because it can be changed into another prime (513004351031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256502175665 + 256502175666.

It is an arithmetic number, because the mean of its divisors is an integer number (256502175666).

Almost surely, 2513004351331 is an apocalyptic number.

513004351331 is a deficient number, since it is larger than the sum of its proper divisors (1).

513004351331 is an equidigital number, since it uses as much as digits as its factorization.

513004351331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100, while the sum is 29.

Adding to 513004351331 its reverse (133153400315), we get a palindrome (646157751646).

The spelling of 513004351331 in words is "five hundred thirteen billion, four million, three hundred fifty-one thousand, three hundred thirty-one".